ie, n vectors that will let it span the whole subspace
ex, basis vector of a line is 1 vector; basis vectors of a plane are 2 vectors
If we have a basis {x(1),...,x(m)} for a subspace, S, then we can uniquely write any element in the subspace as a Linear Combination of elements in that basis.
That is, any x∈S can be written as x=i=1∑dαix(i), for an appropriate α
To prove:
2 conditions
There is no linear combination that can escape the subspace?
If the n-vectors a1,...,ak are linearly independent, then k≤n.
A linearly independent collection of n-vectors can have at most n elements.
ie. Any collection of n+1 or more n-vectors is linearly dependent.