Description:
- Given a set of jobs which job starts at and finishes at
- How to do the maximum of mutually compatible jobs in a given time frame
Earliest Finish Time First Algorithm:
- )
- Sort all job by the finishing time
- Let schedule, S, be a set of jobs
- loop thru all job:
- if the job is compatible with S
- add the job
- if the job is compatible with S
- return S